一轴由一对7211AC的轴承支承，Fr1=3300N，Fr2=1000N，Fx=900N，如图。试求两轴承的当量动载荷P。（S=0.68Fr，e=0.68，X=0.41，Y=0.87）
正确答案:
S=0.68Fr
S1=0.68Fr1=0.68×3300N=2244N
S2=0.68Fr2=0.68×1000N=680N
S2+Fx=680+900=1580N1=S1=2244N
Fa2=S1-Fx=2244-900=1344N
Fa1/Fr1=2244/3300=0.68=e
Fa2/Fr2=1340/1000=1.344>e
P1=3300N
P2 = 0.41×1000+0.87×1344=1579N
S1=0.68Fr1=0.68×3300N=2244N
S2=0.68Fr2=0.68×1000N=680N
S2+Fx=680+900=1580N
Fa2=S1-Fx=2244-900=1344N
Fa1/Fr1=2244/3300=0.68=e
Fa2/Fr2=1340/1000=1.344>e
P1=3300N
P2 = 0.41×1000+0.87×1344=1579N
答案解析:有
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