如图所示,求Rab间的等效电阻。已知:R1=2Ω,R2=4Ω,R3=6Ω,R4=8Ω,R5=10Ω
正确答案:
R1与R2并联、R4与R5并联以后两者再与R3串联
Rab=(R1×R2/(R1+R2))+(R4×R5/(R4+R5))+R3
=2×4/6+8×10/18+6
=1.33+4.44+6
=11.8(Ω)
Rab=(R1×R2/(R1+R2))+(R4×R5/(R4+R5))+R3
=2×4/6+8×10/18+6
=1.33+4.44+6
=11.8(Ω)
答案解析:有
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