计算题:取长度为0.5m的某种蚕丝绳,测得其干闪电压为170kV,问在良好天气中对500kV系统的设备进行带电作业时,地电位操作工手握绝缘绳的位置与带电体间不得小于多少米?(计算时不考虑各种过电压的影响。)
正确答案:
带电体对地的电位即是系统的相电压,为![](https://www.274949.com/images/2020-04/01/e8kp7ott.jpg)
良好天气下蚕丝绳的耐电强度为![](https://www.274949.com/images/2020-04/01/f4n7dade.jpg)
蚕丝绳在系统相电压作用下的闪络距离为![](https://www.274949.com/images/2020-04/01/bplpf14o.jpg)
地电位操作工手握绝缘绳的位置与带电体间不小于0.85m。
![](https://www.274949.com/images/2020-04/01/e8kp7ott.jpg)
良好天气下蚕丝绳的耐电强度为
![](https://www.274949.com/images/2020-04/01/f4n7dade.jpg)
蚕丝绳在系统相电压作用下的闪络距离为
![](https://www.274949.com/images/2020-04/01/bplpf14o.jpg)
地电位操作工手握绝缘绳的位置与带电体间不小于0.85m。
答案解析:有
![](/editor/images/201705/qrcode_for_gh_573e2a458573_258.jpg)
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