电解液由0.05%KI,0.06%NaN3和0.5%CH3COOH的水溶液配成,现欲配制lkg电解液,问需KI,NaN3,CH3COOH各多少克?
正确答案:
KI:1000×0.05%=0.5g
NaN3:1000×0.06%=0.6g
CH3COOH:1000×0.5%=5g
需要KI,NaN3,CH3COOH分别为0.5g、0.6g、5g。
NaN3:1000×0.06%=0.6g
CH3COOH:1000×0.5%=5g
需要KI,NaN3,CH3COOH分别为0.5g、0.6g、5g。
答案解析:有
![](/editor/images/201705/qrcode_for_gh_573e2a458573_258.jpg)
微信扫一扫手机做题