计算题:已知某管材拉伸前外径为58mm,壁厚为2.8mm,拉伸后管材的外径为34mm,壁厚为1.36mm,计算该管材的延伸系数λ和变形程度δ%?
正确答案:
λ=[(58-2.8)×2.8]÷[﹙34-1.36﹚×1.36]
=154.56÷31.28
=4.94
δ%=[﹙154.56-31.28﹚÷154.56]×100%
=79.76%
该管材的延伸系数为4.94,变形程度为79.76%。
=154.56÷31.28
=4.94
δ%=[﹙154.56-31.28﹚÷154.56]×100%
=79.76%
该管材的延伸系数为4.94,变形程度为79.76%。
答案解析:有
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